The block was originally 50.0 grams. Here is the Part C figure...
http://imageshack.us/photo/my-images/268/96277608.jpg/
http://imageshack.us/photo/my-images/268/96277608.jpg/
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Hi Andrew!
My suggestion is as follows:
The difference among the two weights corresponds to that of the liquid that has been moved, that is a quantity of liquid whose volume is equal to that of the solid in examination.
........................... weight in air
Density = ----------------------------------------…
...............(weight in air - weight in the liquid)
...............50/(50 – 5.6) = 50/44.4 = 1.12612 g/cm^3
In conclusion, the density is for definition the ratio between the weight in air of a solid and the loss of weight that happens when it is dipped in a liquid.
Bye from Italy,
C6H6
My suggestion is as follows:
The difference among the two weights corresponds to that of the liquid that has been moved, that is a quantity of liquid whose volume is equal to that of the solid in examination.
........................... weight in air
Density = ----------------------------------------…
...............(weight in air - weight in the liquid)
...............50/(50 – 5.6) = 50/44.4 = 1.12612 g/cm^3
In conclusion, the density is for definition the ratio between the weight in air of a solid and the loss of weight that happens when it is dipped in a liquid.
Bye from Italy,
C6H6