A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 651 m/s. The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.020 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?
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vertical fall = v = (g/2) x time ^2.....0.02 = (9.81/2) t^2........so....t = 0.064 sec.
horizontal distance = h = speed x time = 651 x 0.064 = 41.57 m
horizontal distance = h = speed x time = 651 x 0.064 = 41.57 m