Solve the three equations for x.
x - c / c + a = a
y = 5/9 (x - 32)
A = 2(pi)(r^2) + 2(pi)(rx)
Thanks! Even if you set it up and explain how to get the answer, that would be fine too.
x - c / c + a = a
y = 5/9 (x - 32)
A = 2(pi)(r^2) + 2(pi)(rx)
Thanks! Even if you set it up and explain how to get the answer, that would be fine too.
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1.) I am not sure what it is. I will show three different equations, and you pick the one that matches your problem.
(x - c) / (c + a) = a
x - c = a(c + a)
x = a(c + a) + c
x - (c / c) + a = a
x - (c / c) = 0
x = c / c
x = 1
[(x - c) / c] + a = a
(x - c) / c = 0
x - c = 0
x = c
2.) y = 5/9 (x - 32)
9/5 y = x - 32
9/5 y + 32 = x
3.) A = 2(pi)(r^2) + 2(pi)(rx)
A = 2r(pi)[r + x]
A / 2r(pi) = r + x
x = A / 2r(pi) - r
(x - c) / (c + a) = a
x - c = a(c + a)
x = a(c + a) + c
x - (c / c) + a = a
x - (c / c) = 0
x = c / c
x = 1
[(x - c) / c] + a = a
(x - c) / c = 0
x - c = 0
x = c
2.) y = 5/9 (x - 32)
9/5 y = x - 32
9/5 y + 32 = x
3.) A = 2(pi)(r^2) + 2(pi)(rx)
A = 2r(pi)[r + x]
A / 2r(pi) = r + x
x = A / 2r(pi) - r
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x - c / c + a = a ..... multiply both sides by (x-c) = a(c+a) left side cancels out, next distribute (x-c) = ac + a^2 lastly add the +c over the right.
y = 5/9 (x - 32) distribute the 5/9 to both x and -32 then you get y = 5x/9 - 5 add 5 to the other side then multiply by 9 on both sides and finally divide by 5.
y = 5/9 (x - 32) distribute the 5/9 to both x and -32 then you get y = 5x/9 - 5 add 5 to the other side then multiply by 9 on both sides and finally divide by 5.