Do you mean 5^(x^2) - 2x = 1/5? Or is it 5^(x^2 - 2x) = 1/5?
For the first one, it's going to take logs and all kinds of other tricks.
For the second one, it's easy, since 1/5 = 5^(-1)
So then x^2 - 2x = -1, and you can use the quadratic equation to solve that. Actually, you should be able to solve it by quick inspection.
For the first one, it's going to take logs and all kinds of other tricks.
For the second one, it's easy, since 1/5 = 5^(-1)
So then x^2 - 2x = -1, and you can use the quadratic equation to solve that. Actually, you should be able to solve it by quick inspection.