Solve using the quadratic formula x^2+22x-121=0

please explain

Standart quadratic formula: ax^2+bx+c=0
In your task: a=1, b=22, c=-121
First you need to find a discriminant D=b^2-4ac
D=22^2-4*(-121)=484+484=968
x1=(-b+sqrt(D))/2a
x2=(-b-sqrt(D))/2a
sqrt(D)=sqrt(968)=22sqrt(2)
Therefore x1=(-22+22sqrt(2))/2=
=-11+11sqrt(2)
x2==(-22-22sqrt(2))/2=
=-11-11sqrt(2)

a=1 b=22 c=-121

x=-22+/- sq rt 22^2-4(1)(-121)/2

x=-22+/- s qrt 484-484/ 2
x=-22/2= x=-11 there is only one root because you have sq rt 0

-22 plus or minus square root(22^2-4*1*-121) all divided by 2*1

x ^ 2 + 22x - 121 = 0

(x + 11) (x + 11) = 0
take one of the brackets as they are both similar = 0
x + 11 = 0
x = -11