Math question, 3[2y-3(y+4)]-1=18
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Math question, 3[2y-3(y+4)]-1=18

[From: ] [author: ] [Date: 12-01-23] [Hit: ]
Since you cannot add y and 4 together (they are the most inner parentheses), you distribute the -3 to y and 4,Then, you combine what you can inside of the brackets/parentheses. Since 2y and -3y are like terms, you combine them,......
The math problem is 3[2y-3(y+4)]-1=18, can you please explain how you do it? Thank you!

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Following PEMDAS (parentheses, exponents, multiplication-division, and addition-subtraction), you first work inside of the parentheses. Since you cannot add y and 4 together (they are the most inner parentheses), you distribute the -3 to y and 4, giving you:
3[2y-3y-12]-1=18
Then, you combine what you can inside of the brackets/parentheses. Since 2y and -3y are like terms, you combine them, giving you:
3[-y-12]-1=18
Then, you distribute the 3 to -y and -12:
-3y-36-1=18
You have to clear up the left side again, so you subtract 1 from -36:
-3y-37=18
To eliminate the -37 on the left side, because you want to get the variable by itself, you add 37 to both sides:
-3y=55
Now, you divide -3 from both sides:
y=-18 and 1/3

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Get y by itself on one side, but first you need to simplify the equation.
3[2y-3(y+4)]-1=18 multiply -3 and (y+4)
3[2y-3y-12]-1=18 subtract 3y from 2y
3[-1y-12]-1=18 multiply 3 and (-y-12)
-3y-36-1=18 add -36 and -1
-3y-37=18 add 37 to both sides of the equation
-3y=55 Divide both side by -3 to get the y by itself
y=-55/3

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1. First distribute -3 into the y+4 in parenthesis:
3(2y-3y-12)-1=18
2. Now solve everything in the parenthesis:
3(-y-12)-1=18
3. Now distribute the 3 into the -y-12 in parenthesis:
-3y-36-1=18
4. Now 1 from -36 to get -37, then add 37 to each side to get rid of the -37 on the left side.
-3y-37=18
-3y=55
5. now divide both sides by -3 to get y
y=-18.3333333

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here given 3[2y - 3(y+4)] - 1 = 18
1st open small brackets
3[2y -3y -12] - 1 = 18
Again, open big bracket by 3.
or, 3[-y - 12] - 1= 18
or, -3y - 36 - 1= 18
or, -3y -37=18
arrange variable in one side and number another side.
or, -37-18= 3y
or, - 55 = 3y
or, - 55/3= y
or, y = -55/3
or, y = -18 whole 1/3 is the answer.

hope it helps you.

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3[2y-3(y+4)]-1=18
first you have to put the second 3 in
3[2y-3y+12]-1=18
then the first 3
6y-9y-36-1=18
6y-9y=55
-3y=55
y=-55/3

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or, 3[2y-3y-12}-1= 18
or, 6y- 9y -36 - 1 = 18
or, - 3y -37 = 18
or, -3y = 18 + 37
or, -3y =55
then, y = - 55/3 tis is the answerr.........

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y = -55/3

~Kevin.
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