Use the squeeze theorem method to find:
limit x^2 ( cos 1 / x )^3
x->0
Thanks :)
limit x^2 ( cos 1 / x )^3
x->0
Thanks :)
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Bound it below by -x^2, bound it above by x^2 (since cosine is bounded by -1 and 1) then use the fact -x^2 and x^2 go to zero when you twke the limit.