For d(t)=t^2, find [f(t+h)-f(t)]/h

need help with the math problem. would really appreciate it if someone could please explain it to me. thanks!!

I assume you mean, [d(t+h)-d(t)]/h
[(t+h)^2-t^2]/h
[t^2+2th+h^2-t^2]/h
[2th+h^2]/h
2t+h

this is the formula for finding the slope/ derivative

f(t+h)- just like functions let t=(t+h), thus is equal to (t+h)^2
f(t)- is just equal to t^2

now substitue
[(t+h)^2 -t^2]/h
[t^2+2ht+h^2-t^2]/h
cancel t^2/ or just simplify
(2ht+h^2)/h
extract h to cancel
[h(2t+h)]h
cancel h
thus is eual to 2t+h

2t+h

suck my ballz