The limit of this as x approaches positive infinity:
( ( 4^(x) ) - 1 ) / ( 4^(x+1) )
Thanks.
( ( 4^(x) ) - 1 ) / ( 4^(x+1) )
Thanks.
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Use L'Hospital's rule.
Differentiate numerator and denomenator.
You will get 4^xlog4/4^(x+1)log4
Log 4 cancels and also 4^x.
So the answer will be 1/4.
Differentiate numerator and denomenator.
You will get 4^xlog4/4^(x+1)log4
Log 4 cancels and also 4^x.
So the answer will be 1/4.
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( ( 4^(x) ) - 1 ) / ( 4^(x+1) )
= (1/4) [ 1 - 1/(4^x) ]
And since 1/(4^x) goes to zero as x -> +inf, the original expression goes to 1/4
= (1/4) [ 1 - 1/(4^x) ]
And since 1/(4^x) goes to zero as x -> +inf, the original expression goes to 1/4
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1/4
use Daiii's method. no need to use l' hospitals rule here.
use Daiii's method. no need to use l' hospitals rule here.