PLEASE HELP: CHEMISTRY, reaction table
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PLEASE HELP: CHEMISTRY, reaction table

[From: ] [author: ] [Date: 12-01-23] [Hit: ]
0 ? ?How do you get the question marks? Please help and explain if you can!-Whats happening is that an equilibrium is forming. So from the start,......
Complete a reaction table (in moles) for the reaction of 2.17 mol Al and 4.97 mol HCl.

2Al + 6HCl 2AlCl3 + 3H2
initial 2.17 4.97 0 0
delta ? -4.97 ? ?
final ? 0 ? ?

How do you get the question marks? Please help and explain if you can!

-
What's happening is that an equilibrium is forming. So from the start, having placed these compounds in a container, you're going to subtract _x moles from them, _ being their coefficients, and add _x to the other side.

2Al + 6HCl ---------> 2AlCl3 + 3H2

-2x -6x +2x +3x

You can find x because you have 6x already. 6x = 4.97, so x = 0.828


-2(0.828) -4.97 +2(0.828) +3(0.828)

Subtract or add these numbers from reactants and products, and at equilibrium you'll have the following

0.51 0 1.66 2.48
1
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