Math homework help..? Thanks

A) 27a^2b^5-45abc+3a^4b^2c
B) 36r^3p^5q+24r^4p^4-12r^2p
Thanks for the help... And If you can help with these? Thanks so much!
C) 3a^3b-12ab^3
D) 8x^2-52xy+60y^2

= 27a²b⁵ - 45abc + 3a⁴b²c
= 3ab(9ab⁴ - 15c + a³bc)
= 3ab(9ab⁴ + c[a³b - 15])

Answer A): 3ab(9ab⁴ - 15c + a³bc) OR 3ab(9ab⁴ + c[a³ - 15])
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= 36r³p⁵q + 24r4p⁴ - 12r²p
= 12r²p(3rp⁴q + 2r²p³ - 1)
= 12r²p(rp[3p³q + 2rp²] - 1)

Answer B): 12r²p(3rp⁴q + 2r²p³ - 1) OR 12r²p(rp[3r³q + 2rp²] - 1)
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= 3a³b - 12ab³
= 3ab(a² - 4b²)
= 3ab(a + 2b)(a - 2b)

Answer C): 3ab(a + 2b)(a - 2b)
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1st factor is 4:
= 8x² - 52xy + 60y²
= 4(2x² - 13xy + 15y²)

Other factors:
2x² - 13xy = - 15y²
x² - 13/4xy = - 15/2y² + (- 13/4y)²
x² - 13/4xy = (- 120 + 169)/16y²
(x - 13/4y) = 49/16y²
x - 13/4y = ± 7/4y

= x - 13/4 + 7/4y, = x - 6/4y, = x - 3/2y, = 2x - 3y
= x - 13/4y - 7/4y, = x - 20/4y, = x - 5y

Answer D): 4(2x - 3y)(x - 5y)

i would assume factoring :

A) 3 * a * b * ( 9ab^4 - 15c+ a^3bc )

B) 12 * r^2 * p * ( 3rp^4q + 2r^2p^3 - 1 )

C) 3 * a * b * ( a^2 - 4b^2 ) ------> 3ab * ( a - 2b)(a + 2b)

D)

4 * ( 2x^2 - 13xy + 15y^2 )
4 * ( 2x - 3y ) * (y - 5y )

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