Hikers travel x km by bus at 48km/h. They walk back along the same route at an average speed of 4.8km/h. If they arrive back 24 hours after setting our in the bus (allowing 2 hours for lunch), how far must the bus take them?
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Distance = speed × time
time = distance/speed
let the distance travelled be x km
time by bus = x/48
time for return = x/4.8
total time
x/48 + x/4.8 = 24 – 2 = 22
x/48 + 10x/48 = 22
x + 10x = 22 × 48
11x = 22 × 48
x = 2 × 48
= 96 km
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time = distance/speed
let the distance travelled be x km
time by bus = x/48
time for return = x/4.8
total time
x/48 + x/4.8 = 24 – 2 = 22
x/48 + 10x/48 = 22
x + 10x = 22 × 48
11x = 22 × 48
x = 2 × 48
= 96 km
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