an odd number can be represented in 2n+1 form where n is an integer >(-1)
so take any five odd numbers
add it
2a+1 + 2b+1 + 2c+1 + 2d+1 + 2e+1 = 50 (given by you as their sum is 50)
2(a+b+c+d+e) + 5 = 50
2(a+b+c+d+e) = 45
look above equation carefully
there 2(a+b+c+d+e) is an even number since all a,b,c,d and e are integers there is no fraction
so 2(a+b+c+d+e) is even only
so it cannot be 45 which is odd
so sum of any combination of 5 odd numbers cannot be 50
i think my answer is helpful to you
so take any five odd numbers
add it
2a+1 + 2b+1 + 2c+1 + 2d+1 + 2e+1 = 50 (given by you as their sum is 50)
2(a+b+c+d+e) + 5 = 50
2(a+b+c+d+e) = 45
look above equation carefully
there 2(a+b+c+d+e) is an even number since all a,b,c,d and e are integers there is no fraction
so 2(a+b+c+d+e) is even only
so it cannot be 45 which is odd
so sum of any combination of 5 odd numbers cannot be 50
i think my answer is helpful to you
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sum of 5 odd numbers are always odd. so the sum cant be 50.