10 pi= pi2r
r=5
A=pi5^2
25pi
78.50
r=5
A=pi5^2
25pi
78.50
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Follow the rule of circumference.
C = 2πr
Substitute 10π for C and solve for r.
10π = 2πr
r = 5
The radius is 5 inches. Now follow the rule of area.
A = πr^2
Substitute r.
A = π(5)^2
The area is 25π square inches.
C = 2πr
Substitute 10π for C and solve for r.
10π = 2πr
r = 5
The radius is 5 inches. Now follow the rule of area.
A = πr^2
Substitute r.
A = π(5)^2
The area is 25π square inches.
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Circumference = 2 X pi X r = 10 X pi
2 X r = 10
r = 5"
Area = pi X r X r = 25pi square inches ANSWER
2 X r = 10
r = 5"
Area = pi X r X r = 25pi square inches ANSWER
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circumference = 2*pi*r
10*pi = 2*pi*r
r = 5 inches
area = pi * r^2
area = pi (5)^2
area = 25*pi square inches
10*pi = 2*pi*r
r = 5 inches
area = pi * r^2
area = pi (5)^2
area = 25*pi square inches