Finding the Half-Life Question
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Finding the Half-Life Question

[From: ] [author: ] [Date: 11-11-27] [Hit: ]
(1/2)^n = 0.n log 0.5 = log 0.n = 0.60 min divided by 0.91254 = 65.......
A radioactive isotope decayed to 1732 of its original mass after 60 minutes. Find the half-life of this radioisotope.

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You typed '1732' where you may have meant 1/732 or 17/32. Let's use 17/32.

17/32 = 0.53125 (this is the decimal amount that remains)

(1/2)^n = 0.53125

n log 0.5 = log 0.53125

n = 0.91254 (this is how many half-lives have elapsed)

60 min divided by 0.91254 = 65.75 min (this is the half-life, which you may round off to 66 min, if you so desire)
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