How do you use the decay mode to write the transmuation reaction for a radioisotope
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How do you use the decay mode to write the transmuation reaction for a radioisotope

[From: ] [author: ] [Date: 11-11-27] [Hit: ]
Rn-222 Alpha decaythis means Rn-222 -->alpha(mass 4,Ne-10 positron decaythis means Ne-10 -->e(0 mass, +1 charge)+ F-10a proton in the nucleus is converted to a neutron, so no mass gain or loss,......
I would just like to know how to do this so I can answer the questions on my lab. However, if anyone has time to answer one or two of the paticular questions below just so I know what I'm doing that would be great. Thanks.

C-14 Beta decay,
Rn-222 Alpha decay,
U-238 Alpha decay,
Co-60, Beta decay,
I-131 Beta decay,
N-16 Beat decay,
and Ne-10 positron decay.

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The decay mode gives you one product and you balance the reaction so that you have the same number of protons and neutrons on both sides. BTW, you do know that beta decay means that a neutron in the nucleus changes to a proton?

C-14 Beta decay now this means C-14 --> e(0 mass, -1 charge) + N-14 the nucleus gains a proton, moving the element one notch up, but gains no mass.

Rn-222 Alpha decay this means Rn-222 --> alpha(mass 4, +2 charge) + Po-218 you lose 4 mass units and two spaces back on the periodic chart

Ne-10 positron decay this means Ne-10 --> e(0 mass, +1 charge) + F-10 a proton in the nucleus is converted to a neutron, so no mass gain or loss, but one step back on the periodic table

hope that helps some
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