If a signal is expressed in this form v=5V(sin377t+32°), then its Vp-p is equal to:

a. 2.5V
b. 3.535V
c. 5V
d. 7.072V
e. 10V

Any and all help is greatly appreciated, THANK YOU!

i think the answer is 10v as the equation V=Vpsin(a-k),,,,,where a is angle,k is constant ,,Vp is peak voltage
Vp=5
this equation follow sine graph,so peak to peak is 5+5=10v
am i correct
sorry if my answer is not correct..........

A-level students should help each others.Thanks for vote.

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A sin function varies from -1 to +1. So when you have A * sin(something), it varies from -A to +A.

Therefore the peak-to-peak range is 2A where A is the coefficient in front of the sine.

Apply that rule to your equation.