a. 2.5V
b. 3.535V
c. 5V
d. 7.072V
e. 10V
Any and all help is greatly appreciated, THANK YOU!
b. 3.535V
c. 5V
d. 7.072V
e. 10V
Any and all help is greatly appreciated, THANK YOU!
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i think the answer is 10v as the equation V=Vpsin(a-k),,,,,where a is angle,k is constant ,,Vp is peak voltage
Vp=5
this equation follow sine graph,so peak to peak is 5+5=10v
am i correct
sorry if my answer is not correct..........
Vp=5
this equation follow sine graph,so peak to peak is 5+5=10v
am i correct
sorry if my answer is not correct..........
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A-level students should help each others.Thanks for vote.
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A sin function varies from -1 to +1. So when you have A * sin(something), it varies from -A to +A.
Therefore the peak-to-peak range is 2A where A is the coefficient in front of the sine.
Apply that rule to your equation.
Therefore the peak-to-peak range is 2A where A is the coefficient in front of the sine.
Apply that rule to your equation.