I have a car with mass 1500kg that skids for 14.5m
The coefficient of friction is 0.8
However, after skidding for 14.5m the car is still travelling at 17m/s.
what is the initial velocity and what is the acceleration (or deceleration).
Thanks!
The coefficient of friction is 0.8
However, after skidding for 14.5m the car is still travelling at 17m/s.
what is the initial velocity and what is the acceleration (or deceleration).
Thanks!
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Acceleration due to friction = -μg = 0.8*9.8 = - 7.84 m/s^2
Using v^2 = u^2 + 2as
U^2 = 17^2 –2 * ( -7.84)14.5
U = 27.27 m/s
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Using v^2 = u^2 + 2as
U^2 = 17^2 –2 * ( -7.84)14.5
U = 27.27 m/s
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k ( coefficent of friction) = 0.8
g = 10 m/s2
m= 1500 kg
Force on the car while skidding = k*m*g = 0.8*1500*10
Retardation on the body = F/m = 0.8*1500*10/1500 = 8m/s2 ( accel is -8m/s2)
now by eqn of motion
v^2 - u^2 = 2as
u^2 = v^2 -2as
= 17*17 + 2*8*14.5 = 289 + 232 = 521
u = 22m/s (approx)
g = 10 m/s2
m= 1500 kg
Force on the car while skidding = k*m*g = 0.8*1500*10
Retardation on the body = F/m = 0.8*1500*10/1500 = 8m/s2 ( accel is -8m/s2)
now by eqn of motion
v^2 - u^2 = 2as
u^2 = v^2 -2as
= 17*17 + 2*8*14.5 = 289 + 232 = 521
u = 22m/s (approx)
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use energy
(1/2)mv^2-Fr*D=0
(1/2)*1500*v^2-0.8*1500*9.8*14.5=0
Solve for v.
v=15.08m/s
(1/2)mv^2-Fr*D=0
(1/2)*1500*v^2-0.8*1500*9.8*14.5=0
Solve for v.
v=15.08m/s