im going to make a chart like it is in the book. i need help please..
10.Face of notehave to find the Interest and the Amount due at Maturity$5003 years of time12% rate
11.$1503months18%
12.$9202
How come the phase shift of g(x) = 2cos(3x-2) is not 2 rad to the right?
I get it but I dont know how to explain it in mathematical words...
Can someone please help me?-The general form of the sinuso
What is the standard form of the equation of the conic:
4x^2 - 5y^2 - 16x - 30y - 9 = 0
Can you please show the steps? Thanks!-4x^2 - 5y^2 - 16x - 30y - 9 = 0
4x^2 - 16x - 5y^2 - 30y = 9
4 * (x^2 - 4x
4th radical of (a^2/b) ... how would you use logs to solve it?
(2+ √3)/(2-√3) ... what is it equivalent to?
log4 + logx =28 ... find x.
Please include explanations. Thanks in advance!!-4th radical
the question is like y_2(t)=t^(-1)
but in the steps they have put the problem like y_2(t)=1/t
so i was wondering is that fine??
thanks-Yes.t^(-n) = 1/(t^n) in general and in this case t^(-1 = 1/(t^1
I need to know how to simplify this please help me.the / mark stands for division:)-Hi Nicole!
Left side:
Note:csc x = 1/sin x
csc x
-----------
sin x
1
---------------------
sin x * sin x
1
0.25 + x = 0.455
how do I get rid of decimals, what do i multiply by and why
0.25x + 3/4 + 5/12x = 0.3882
how would i get rid of fractions and decimals
do i multiply by lcm or something what is it b
How do I evaltuate this limit as n goes to infinity?
(n^n)/((n+3)^(n+1))
Please show your working
Thanks, James-What if we factor the denominator (n + 3)^(n + 1) as (n + 3)(n + 3)^n ?
Then, our ra
f(x) = tan²(x^3)
f(x) = [tan(x^3)]²
Use the power rule and chain rule:
f (x) = 2tan(x^3) * d/dx[tan(x^3)]
Use the chain rule and the fact that d/dx[tan(x)] = sec²(x):
2tan(x^3) * sec²(x^3) * d/dx[x^3]
It is simple but confusing there is a lot of trail and error that and I have tried for awhile. So here it is Amber was given 100 dollars and told to spend it purchasing exactly 100 animals at the pet
I do not understand this problem; if you know the answer, a step-by-step explanation would be greatly appreciated!
Thanks in advance.-remember:
sec(A) = 1/cos(A)
tan(A) = sin(A)/cos(A)
So:
sec(x)ta
Given the fact that sigma n=1 to infinity cos(nx)/n^2 = x^2/4 - pi*x/2 + pi^2/6if 0
sigma n=1 to infinity (-1)^(n+1) / (2n-1)^3 = pi^3 / 32
My work: I took the derivative of the Taylor series with