cos(360°+Θ). cos(90°-Θ)
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sin(-Θ) cos(x-180°)tan(180°)
prove the identity (tan^2Θ -sixn^2Θ)1/(tan^2Θ.sin^2Θ) =1
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sin(-Θ) cos(x-180°)tan(180°)
prove the identity (tan^2Θ -sixn^2Θ)1/(tan^2Θ.sin^2Θ) =1
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Are you sure you've noted the question correctly?
Everything at the bottom of the fraction is being multiplied. You have tan180 there. Tan180 is equal to 0. If you multiply that by everything else there, the bottom of the fraction will become 0. And hence everything that's on the top will be divided by 0 which mathematically can not happen.
Everything at the bottom of the fraction is being multiplied. You have tan180 there. Tan180 is equal to 0. If you multiply that by everything else there, the bottom of the fraction will become 0. And hence everything that's on the top will be divided by 0 which mathematically can not happen.