How come the phase shift of g(x) = 2cos(3x-2) is not 2 rad to the right?
I get it but I don't know how to explain it in mathematical words...
Can someone please help me?
I get it but I don't know how to explain it in mathematical words...
Can someone please help me?
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The general form of the sinusoidal equation is
y = acos(b(x - c)) + d
And so you gotta leave the x as it is factored out. And since the coefficient 3 is attached to it, you gotta pull it out.
y = 2cos(3x - 2)
= 2cos(3(x - (2/3)))
THus, it's 2/3 rad to the right (positive direction)
Hope this helps :D
y = acos(b(x - c)) + d
And so you gotta leave the x as it is factored out. And since the coefficient 3 is attached to it, you gotta pull it out.
y = 2cos(3x - 2)
= 2cos(3(x - (2/3)))
THus, it's 2/3 rad to the right (positive direction)
Hope this helps :D