This is the question:
Marissa is doing a Tarot reading in which she must pick 6 cards from a deck of 72. The order of their selection is not important.
How many different readings are possible?
Marissa does not want to see the Fool card. How many of the possible readings do not feature the Fool?
I figured out part A but can someone please help me with the second part?
Marissa is doing a Tarot reading in which she must pick 6 cards from a deck of 72. The order of their selection is not important.
How many different readings are possible?
Marissa does not want to see the Fool card. How many of the possible readings do not feature the Fool?
I figured out part A but can someone please help me with the second part?
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Pretty straight forward.
72 C 6 =
72! / (66! 6!)
72 x 71 x......66 x ... 1 / (66x 65 x 64 x ... 1 x 6 x 5 x 4 x 3 x 2 x 1)
72 x 71 x 70 ...x 66 / 6 x 5 x 4 x 3 x 2
The second part simply involves removing the fool card. Same problem, but use a 71 card deck
always,
tony
72 C 6 =
72! / (66! 6!)
72 x 71 x......66 x ... 1 / (66x 65 x 64 x ... 1 x 6 x 5 x 4 x 3 x 2 x 1)
72 x 71 x 70 ...x 66 / 6 x 5 x 4 x 3 x 2
The second part simply involves removing the fool card. Same problem, but use a 71 card deck
always,
tony
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The second part is the same as the first, except for you don't count the fool card. Instead of doing 72 C 6, do 71 C 6. so the answer to part b is 14,328,999.