What is the surface area of a cylinder whose base diameter is 10 cm and whose height is 12 cm? Round your answer to the nearest tenth.
A)552.7
B)555.6
C)341.2
D)534.1
PLEASE SOMEONE HELP! IM LOST ON THIS QUESTION
A)552.7
B)555.6
C)341.2
D)534.1
PLEASE SOMEONE HELP! IM LOST ON THIS QUESTION
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surface area of a cylinder is = πr^2 (top) + πr^2 (bottom) + 2πrh
r= radius of the circle = 5cm NOTE: radius = diamater/2
h= height = 12cm
plug it in
π(5^2) + π(5^2) + 2π(5)(12)
25π + 25π + 120π = 170π = 170*3.1415926 =534.070742 = 534.1
Answer D
dnadan1
r= radius of the circle = 5cm NOTE: radius = diamater/2
h= height = 12cm
plug it in
π(5^2) + π(5^2) + 2π(5)(12)
25π + 25π + 120π = 170π = 170*3.1415926 =534.070742 = 534.1
Answer D
dnadan1
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ANS: D) (=534.10 cm^2
Given: d = 2r = 10 cm or r = 5 cm; h = 12 cm
Surface Area = (2 • π • r²) + (2 • π • r • height) :Where (2 • π • r²) is the surface area of the "ends"
=(2 • π •5^2) + (2 • π •5 • 12)
= 157 + 376.80
= 533.80 ~ 534
Given: d = 2r = 10 cm or r = 5 cm; h = 12 cm
Surface Area = (2 • π • r²) + (2 • π • r • height) :Where (2 • π • r²) is the surface area of the "ends"
=(2 • π •5^2) + (2 • π •5 • 12)
= 157 + 376.80
= 533.80 ~ 534
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The formula for the surface area of a cylinder is 2*π*r^2 + 2*π*r*h.
Therefore, it's surface area is:
D) 534.1
Therefore, it's surface area is:
D) 534.1