Sorry if the matrix is a little confusing i couldn't copy it correctly.
[1 5 l-6]
[0 3 l17]
A.
x + 5y = -6
3y = 17
B.
y + 5x = -6
3x = 17
C.
x + 5y = -6
x + 3y = 17
[1 5 l-6]
[0 3 l17]
A.
x + 5y = -6
3y = 17
B.
y + 5x = -6
3x = 17
C.
x + 5y = -6
x + 3y = 17
-
In(a) write the second equation as 0x + 3y = 17; now n both equations "kill" the x & y to get 1 5 -6 in row (1) and 0 3 17 in the second, so the answer is (A). Alternatively if you prefer deriving the equation from the matrix, in the first line of the matrix, !inject! an x & y as 1x + 5= = -6 and in the second 0x + 3y = 17, or in the top row, x + 5y = -6, and in the second row 3y = 17