I kinda get it.
Like
81^1/2 you make 2 sqrt 81 than multiply 1
Any other way you know less confusing?
But here the problem I don't get
(7x^1/3)(2x^1/4)
How on earth do you do that?
Like
81^1/2 you make 2 sqrt 81 than multiply 1
Any other way you know less confusing?
But here the problem I don't get
(7x^1/3)(2x^1/4)
How on earth do you do that?
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on your example, what did you do?
81^1/2 is the same as square root (81) = 9
(7x^1/3)(2x^1/4)
First multiply the 7 and 2 together:
14 (x^1/3)(x^1/4)
When multiplying numbers/variables of the same base raised to an exponent, add the exponents.
14 x^(1/3 + 1/4)
Find common denominator:
14 x^(4/12 + 3/12)
14 x^(7/12)
81^1/2 is the same as square root (81) = 9
(7x^1/3)(2x^1/4)
First multiply the 7 and 2 together:
14 (x^1/3)(x^1/4)
When multiplying numbers/variables of the same base raised to an exponent, add the exponents.
14 x^(1/3 + 1/4)
Find common denominator:
14 x^(4/12 + 3/12)
14 x^(7/12)
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When you multiply two terms, you add the indices.
In this case, the indices are 1/3 and 1/4.
So, the power of x will be 1/3 + 1/4 = 7/12
7 times 2 = 14
answer is 14x^7/12
In this case, the indices are 1/3 and 1/4.
So, the power of x will be 1/3 + 1/4 = 7/12
7 times 2 = 14
answer is 14x^7/12