How to solve this system? Elimination method math

3x + 2y = 12
x - 2y = - 4


would you just subtract it? If I used the elimination method that is

in elimination method, you write one variable in terms of other (for both equations) and equate the two .

like in the above example, for first equation ,

3x+2y=12 > x=(12-2y)/3

for second equation ,

x-2y=-4 > x=2y-4

equate both now,
(12-2y)/3=2y-4
12-2y=6y-12
24=8y
y=3

substitue this to find x
x=2y-4
x=2(3)-4=2


therefore, x=2 , y=3

This is called elimination method!

another simple method, add the two equations in your question . 3x+x +2y-2y = 12-4
4x=8 > x=2 , y=3 !!!

Since the coefficient before "y" in both of the equation are inverse to each other (2 and -2), it is suggested that you should eliminate "y" by combining both equation together. By doing so, the result would be 4x = 8, and x = 2

To solve for "y", replace "x=2" in any equation. I pick the 3x+2y=12, therefore 3(2)+2(y)=12
= 2y = 6 (y = 3)

The solution is (x,y) = (2,3)

Elimination ppsssh just do substitution