Simplify the expression and factor... there should be no negative exponents in your answer.
(2x-1)^.5 - (x+2)(2x-1)^-.5
Please show work and explain! Thanks a ton for your efforts! :))
(2x-1)^.5 - (x+2)(2x-1)^-.5
Please show work and explain! Thanks a ton for your efforts! :))
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(2x-1)^.5 - (x+2)(2x-1)^-.5 first off, the .5 power means u take the square root, and the negative one just means you put that over one. so lets re-write it as this:
√(2x-1) - (x+2)/√(2x-1) now multiply the left of the minus sign by √(2x-1)/√(2x-1) so you have a common denominator. then we can combine the numerators:
[(2x-1) - (x+2)] / √(2x-1) distribute the negative 1 to the (x+2)
[2x-1 - x - 2] / √(2x-1) combine like terms in the numerator
(x - 3) / √(2x-1) now we can rationalize by multiplying the fraction by √(2x-1)/√(2x-1) again
(x - 3)√(2x-1) / (2x-1) <-- this is as simplified as we can get
hope this helps
√(2x-1) - (x+2)/√(2x-1) now multiply the left of the minus sign by √(2x-1)/√(2x-1) so you have a common denominator. then we can combine the numerators:
[(2x-1) - (x+2)] / √(2x-1) distribute the negative 1 to the (x+2)
[2x-1 - x - 2] / √(2x-1) combine like terms in the numerator
(x - 3) / √(2x-1) now we can rationalize by multiplying the fraction by √(2x-1)/√(2x-1) again
(x - 3)√(2x-1) / (2x-1) <-- this is as simplified as we can get
hope this helps