A ball with a mass of 300 g is thrown with an initial velocity of 6 m/s to the right. A force of friction of 0.45 N causes the ball to come to a stop. How long did it take the ball to roll to a stop?
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F = ma
Force is negative because it is impeding the motion of the ball.
-0.45 N = (0.3 kg) a
a = -1.5 m/s^2
Now use the equation Vf = Vi + at
0 = 6 + (-1.5)t
t = 4 seconds
Force is negative because it is impeding the motion of the ball.
-0.45 N = (0.3 kg) a
a = -1.5 m/s^2
Now use the equation Vf = Vi + at
0 = 6 + (-1.5)t
t = 4 seconds
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300g = 0.3kg.
Acceleration = (f/m) = 0.45/0.3, = -1.5m/sec^2.
Time to stop = (v/a) = 6/1.5, = 4 secs.
Acceleration = (f/m) = 0.45/0.3, = -1.5m/sec^2.
Time to stop = (v/a) = 6/1.5, = 4 secs.