Please help explain this interval notation problem? {10 points}

here is the equation.
x-2 over x+1 ≥ 0

i dont know how to solve it please i need help.

also im having a little trouble with using vertex formula.
f(x)= x^2-2x-35

for this one im supposed to find the y intercept and x intercepts.

x-2/(x+1)=

x+1/(x+1) -3/(x+1) ≥ 0

-3/(x+1) ≥ -1

1 ≥ 3/(x+1)

1/3≥ 1/(x+1)

for x+1 positive

(x+1)≥3

x≥2

for x+1 negative -1≥x

f(x)= x^2-2x-35= (x-7)(x+5) that means
y=0 for x= 7 and -5; x intercepts
for x=0 y= -35; y intercept

This answer assumes you know a fair amount about multiplying across inequality signs
multiply both sides by x+1, since x+1 can be both positive and negative, to solve for when it is negative we have two inequalities

x-2 greater/equal 0 and x-2 less than/equal 0
so x greater than/equal 2 and x less than or equal -2

(x-2)/(x+1)≥0

-∞ -1 2 +∞
---------------------------
+ + I - - -0+ + +

x belongs to (-∞, -1) U [2, +∞)

f(x)=x^2-2x-35
vertex is for x=-b/2a
the vertex has the coordinates (1,-36)
and is a maxim as the x^2 coefficient is >0