here is the equation.
x-2 over x+1 ≥ 0
i dont know how to solve it please i need help.
also im having a little trouble with using vertex formula.
f(x)= x^2-2x-35
for this one im supposed to find the y intercept and x intercepts.
x-2 over x+1 ≥ 0
i dont know how to solve it please i need help.
also im having a little trouble with using vertex formula.
f(x)= x^2-2x-35
for this one im supposed to find the y intercept and x intercepts.
-
x-2/(x+1)=
x+1/(x+1) -3/(x+1) ≥ 0
-3/(x+1) ≥ -1
1 ≥ 3/(x+1)
1/3≥ 1/(x+1)
for x+1 positive
(x+1)≥3
x≥2
for x+1 negative -1≥x
f(x)= x^2-2x-35= (x-7)(x+5) that means
y=0 for x= 7 and -5; x intercepts
for x=0 y= -35; y intercept
x+1/(x+1) -3/(x+1) ≥ 0
-3/(x+1) ≥ -1
1 ≥ 3/(x+1)
1/3≥ 1/(x+1)
for x+1 positive
(x+1)≥3
x≥2
for x+1 negative -1≥x
f(x)= x^2-2x-35= (x-7)(x+5) that means
y=0 for x= 7 and -5; x intercepts
for x=0 y= -35; y intercept
-
This answer assumes you know a fair amount about multiplying across inequality signs
multiply both sides by x+1, since x+1 can be both positive and negative, to solve for when it is negative we have two inequalities
x-2 greater/equal 0 and x-2 less than/equal 0
so x greater than/equal 2 and x less than or equal -2
multiply both sides by x+1, since x+1 can be both positive and negative, to solve for when it is negative we have two inequalities
x-2 greater/equal 0 and x-2 less than/equal 0
so x greater than/equal 2 and x less than or equal -2
-
(x-2)/(x+1)≥0
-∞ -1 2 +∞
---------------------------
+ + I - - -0+ + +
x belongs to (-∞, -1) U [2, +∞)
f(x)=x^2-2x-35
vertex is for x=-b/2a
the vertex has the coordinates (1,-36)
and is a maxim as the x^2 coefficient is >0
-∞ -1 2 +∞
---------------------------
+ + I - - -0+ + +
x belongs to (-∞, -1) U [2, +∞)
f(x)=x^2-2x-35
vertex is for x=-b/2a
the vertex has the coordinates (1,-36)
and is a maxim as the x^2 coefficient is >0