How do you solve these problems

(2x^-2)^-4
and
(2r^3)^-4
plz explain
thank you!

You didn't give equations, so you can't solve them\, but you can simplify them.

(2x^-2)^-4
2^-4*(x^-2)^-4
2^-4=1/16
(x^-2)^-4=x^8
1/16*x^8 or x^8/16

(2r^3)^-4
2^-4*(r^3)^-4
2^-4=1/16
(r^3)^-4=r^-12
1/16*r^-12 or 1/(16r^12)

by using These NUTS