How to solve this radical

6x / (2-sqrt(x)=16

6x / (2-√x)=16

6x = 16(2-√x) <--- multiply both sides of equation by (2-√x)
3x = 8(2-√x)
3x = 16 - 8√x
3x - 16 = -8√x
9x^2 - 96x + 256 = 64x
9x^2 - 160x + 256 = 0
(9x - 16)(x - 16) = 0
x = 16/9 or x = 16

But 6*16 / (2-√16) = 6*16 / (2-4) = 6*16/-2 = -48 =/= 16, so 16 is NOT a solution

SOLUTION: 16/9

hope this helped you:D