Easy probability question!:) help^_^
Favorites|Homepage
Subscriptions | sitemap
HOME > > Easy probability question!:) help^_^

Easy probability question!:) help^_^

[From: ] [author: ] [Date: 12-05-01] [Hit: ]
& 1 quarter?Numerator: There are 6C3 = 20 ways to pick 3 nickels.10C2 = 45 ways to pick 2 dimes. And, 4C1 = 4 ways to pick 1 quarter.In total,......
From a bag containing 6 nickels, 10 dimes, & 4 quarters, 6 coins are drawn at random all at once. What is the probability of getting 3 nickels, 2 dimes , & 1 quarter?

-
Missy -

Numerator: There are 6C3 = 20 ways to pick 3 nickels. 10C2 = 45 ways to pick 2 dimes. And, 4C1 = 4 ways to pick 1 quarter. In total, 20x45x4 = 3600 ways to pick 3 nickels, 2 dimes , & 1 quarter.

Denominator: Out of 20 coins, there are 20C6 = 38,760 ways to pick 6 coins.

P = 3600 / 38760 = 30 / 323

Hope that helped
1
keywords: Easy,help,probability,question,Easy probability question!:) help^_^
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .