Find g(x+h) for g(x)=3x^2-4x+6
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g(x) = 3x² – 4x + 6
g(x+h) = 3(x+h)² – 4(x+h) + 6
g(x+h) = 3(x+h)² – 4(x+h) + 6
g(x+h) = 3x² + 6xh + 3h² – 4x – 4h + 6
g(x+h) = 3x² – 4x + 6 + 3h² + 6xh – 4h
g(x+h) = 3x² – 4x + 6 + h(3h + 6x – 4)
g(x+h) = g(x) + h(3h + 6x – 4)
g(x+h) = 3(x+h)² – 4(x+h) + 6
g(x+h) = 3(x+h)² – 4(x+h) + 6
g(x+h) = 3x² + 6xh + 3h² – 4x – 4h + 6
g(x+h) = 3x² – 4x + 6 + 3h² + 6xh – 4h
g(x+h) = 3x² – 4x + 6 + h(3h + 6x – 4)
g(x+h) = g(x) + h(3h + 6x – 4)
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Find g(x+h) for g(x)=3x^2-4x+6
g(x+h) = 3(x+h)^2 - 4(x+h) + 6 =
= 3(x^2 + 2xh + h^2) - 4x - 4h + 6 =
= 3x^2 + 6xh + 3h^2 - 4x - 4h + 6
With the information you provided, this is all you can do.
g(x+h) = 3(x+h)^2 - 4(x+h) + 6 =
= 3(x^2 + 2xh + h^2) - 4x - 4h + 6 =
= 3x^2 + 6xh + 3h^2 - 4x - 4h + 6
With the information you provided, this is all you can do.
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OK. if you want to find g(x+h) then just substitute (x+h) in for x in the function g(x).
This is getting you ready for the definition of a derivative.
This is getting you ready for the definition of a derivative.
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There isn't enough information here to solve this problem. You need a g(h).
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Just substitute x+h in place of x . But i think the question is incomplite