This was in my content but I don't understand it...
f(x) = 2x² - 20x + 45
f(x) = 2(x² - 10x) + 45
= 2(x² - 10x + 25 - 25) + 45
= 2(x² - 10x + 25) - 50 + 45
= 2(x - 5)² - 5
Where does the 24 suddenly appear from?
Many thanks for any help! =)
f(x) = 2x² - 20x + 45
f(x) = 2(x² - 10x) + 45
= 2(x² - 10x + 25 - 25) + 45
= 2(x² - 10x + 25) - 50 + 45
= 2(x - 5)² - 5
Where does the 24 suddenly appear from?
Many thanks for any help! =)
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it is called completing the square
When you have something like
x^2 +bx
and you want to convert it to something like
x^2 +bx +c
take half of the b term, square it, add it and subtract it or add it once to each side of an equation. NOTE: To do this, the coefficient on the x^2 term must be 1.
Example:
x^2 + 10x = 0
take 1/2 of the b term which is 10
so 1/2 of 10 = 5
then square it to get 25
x^2 + 10x + 25 = 25 (to keep the equation balanced)
then you can rewrite as follows
(x + 5)^2 = 25
In your example,
it was simply added it and subtracted it on the same side (essentially adding zero)
x^2 + 10x
x^2 + 10x + 25 - 25 (adding zero doesn't change the equation but allows manipulation)
(x + 5)^2 - 25
Jim
When you have something like
x^2 +bx
and you want to convert it to something like
x^2 +bx +c
take half of the b term, square it, add it and subtract it or add it once to each side of an equation. NOTE: To do this, the coefficient on the x^2 term must be 1.
Example:
x^2 + 10x = 0
take 1/2 of the b term which is 10
so 1/2 of 10 = 5
then square it to get 25
x^2 + 10x + 25 = 25 (to keep the equation balanced)
then you can rewrite as follows
(x + 5)^2 = 25
In your example,
it was simply added it and subtracted it on the same side (essentially adding zero)
x^2 + 10x
x^2 + 10x + 25 - 25 (adding zero doesn't change the equation but allows manipulation)
(x + 5)^2 - 25
Jim
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f(x) = 2x² - 20x + 45
f(x) = 0
x1 = 1/4(20 + 2 √(10)) = [10 + √(10)]/2
x2 = [10 - √(10)]/2
f(x) = 2 {x - [10 - √(10)]/2}*{x - [10 + √(10)]/2}
what are you trying to get in fact?
f(x) = 0
x1 = 1/4(20 + 2 √(10)) = [10 + √(10)]/2
x2 = [10 - √(10)]/2
f(x) = 2 {x - [10 - √(10)]/2}*{x - [10 + √(10)]/2}
what are you trying to get in fact?
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30 = 2· 15 = 2· 3· 5
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There is an error in the solving