If monoprotic acid is titrated with a base, what's the concentration of the acid

56.0 mL of a monoprotic acid is titrated with .165 M NaOH, and 20.1 mL of base is needed to reach the equilibrium point, what's the concentration of the acid?

find moles:
0.0201 Litres) (0.165 moles / Litre) = 0.0033165 moles of NaOH

since 1 mole of a monoprotic acid will react with 1 mole of NaOH:
1 mole HX & 1 mole NaOH ==> 1 NaX & 1 H2O
0.0033165 moles of NaOH reactedf with 0.0033165 moles of HX

find molarity of that 56 ml sample:
( 0.0033165 moles of HX) / 0.0560 Litres) = 0.0592 Molar acid