4>x-3(x+2)?
I couldn't solve this, it would be great if you could help
thanks (:
I couldn't solve this, it would be great if you could help
thanks (:
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4 > x - 3x -6
4 > -2x -6
4 > 2(-x -3)
Divide by 2 on both sides
4/2 > 2/2(-x -3)
2 > -x -3
2 + 3 > -x -3 + 3
5 > -x
Multiply by -1 on both sides
-5 < x
x > -5
4 > -2x -6
4 > 2(-x -3)
Divide by 2 on both sides
4/2 > 2/2(-x -3)
2 > -x -3
2 + 3 > -x -3 + 3
5 > -x
Multiply by -1 on both sides
-5 < x
x > -5
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Let's first treat this as a normal equation:
4=x-3(x+2)
4=x-3x-6
10=-2x
x=-5
Then plot the function in your calculator and you'll see it's higher then 4 left of -5,thus:
x<-5
4=x-3(x+2)
4=x-3x-6
10=-2x
x=-5
Then plot the function in your calculator and you'll see it's higher then 4 left of -5,thus:
x<-5
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0>x-3x-6-4
0>-2x-10
10>-2x
-5>x
0>-2x-10
10>-2x
-5>x