Show that one possible values of angle ABC is 25.8 degrees
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Using the law of sines...
sin BAC / BC = sin ACB / AB.
So sin BAC / 6 = sin 36° / 4.
So sin BAC ≈ 0.88167788.
So BAC ≈ arcsin(0.88167788) = 61.8° or 180° - 61.8° = 118.2°. (Both angles are possible.)
If BAC = 118.2°, then ABC = 180° - (118.2° + 36°) = 25.8°.
sin BAC / BC = sin ACB / AB.
So sin BAC / 6 = sin 36° / 4.
So sin BAC ≈ 0.88167788.
So BAC ≈ arcsin(0.88167788) = 61.8° or 180° - 61.8° = 118.2°. (Both angles are possible.)
If BAC = 118.2°, then ABC = 180° - (118.2° + 36°) = 25.8°.