Prove the trig identity sin^2(x/2)= (cscx-cotx)/2cscx
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Prove the trig identity sin^2(x/2)= (cscx-cotx)/2cscx

[From: ] [author: ] [Date: 11-11-15] [Hit: ]
......
Please help!
We can only work on ONE SIDE
^2 means squared
/ means divided by
Thank you!

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Take RHS

( csc x - cot x ) /2 csc x

= (1/2) - (1/2)cos x

= 1/2(1 - cos x )

= 1/2 (1 - (1 - 2sin^2(x/2))

= 1/2 (2 sin^2(x/2))

= sin^2(x/2)

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(cscx-cotx)/2cscx
= (1/2)(1 - cosx), after multiplying the top and the bottom by sinx
= sin^2(x/2), half angle formula
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keywords: trig,the,sin,cscx,identity,Prove,cotx,Prove the trig identity sin^2(x/2)= (cscx-cotx)/2cscx
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