If the equations below are true, what is the value of y+z

3x+2y+2z=19
3x+y+z=14

first equation can be rewritten as:

3x + 2y + 2z = 19
3x + 2(y + z) = 19

second equation:

3x + y + z = 14
3x + (y + z) = 14

subtract 3x from both sides

(y + z) = 14 - 3x
substitute this into the first equation

3x + 2(14 - 3x) = 19
3x + 28 - 6x = 19
-3x = 19 - 28
-3x = -9
divide both sides by -3
x = 3

(y + z) = 14 - 3x
(y + z) = 14 - 3(3)
(y + z) = 14 - 9

(y + z) = 5 <====