Smallest area for a block of ice
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Smallest area for a block of ice

[From: ] [author: ] [Date: 11-11-14] [Hit: ]
305*9.A = 3.......
A block of ice 30.5 cm thick floating in fresh water just supports a man weighing 801 N. If the specific gravity of ice is 0.917, the smallest area the block can have is

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Ice weight + man weight = water weight

(t*A*ρi)g + Wm = (t*A*ρw)g →

A = Wm/[t*g*(ρw - ρi)] = 801/[.305*9.8*(1000 - 917)]

A = 3.229 m²
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