A bolt having a diameter of 5 mm is loaded so that
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A bolt having a diameter of 5 mm is loaded so that

[From: ] [author: ] [Date: 11-11-13] [Hit: ]
Force,Area = πd²/4 = π(5mm)²/4 = π(0.005m)²/4 = 1.Stress = Force/Area,Force = Stress * Area = 120 MPa * 1.96 x 10^-5 m² = 120 x 10^6 Pa * 1.......
A bolt having a diameter of 5 mm is
loaded so that the shear stress in it is
120 MPa. Determine the value of the
shear force on the bolt.

-
Note: 1 Pa = 1 N/m²

Stress = Force/Area

Stress = 120 MPa, this is given

Force, we need to find that

Area = πd²/4 = π(5mm)²/4 = π(0.005m)²/4 = 1.96 x 10^-5 m²

Stress = Force/Area, so

Force = Stress * Area = 120 MPa * 1.96 x 10^-5 m² = 120 x 10^6 Pa * 1.96 x 10^-5 m² = 2352 N
1
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