Part 1: assume that in interstellar space the distance between 2 electrons is about 0.1 cm. the electric force between the two electrons is repulsive.
Part 2: Calculate the electric force between these two electrons. Use 9x10^9 for the coulomb constant. The magnitude of the charge of the electron is -1.6x10^-19 C (answer in units of N)
Part 3: Calculate the gravitational force between these two electrons. The universal gravitational constant is 6.7x10^-11 and the mass of the electron is 9x10^-31 kg. (answer in units of N)
Part 2: Calculate the electric force between these two electrons. Use 9x10^9 for the coulomb constant. The magnitude of the charge of the electron is -1.6x10^-19 C (answer in units of N)
Part 3: Calculate the gravitational force between these two electrons. The universal gravitational constant is 6.7x10^-11 and the mass of the electron is 9x10^-31 kg. (answer in units of N)
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F=k*q*q/r^2 -- coulombs law.
F=9E9*(-1.6E-19)^2/(.001)^2
F=2.304E-22N
F=Gm1*m2/r^2 -- newtons law of gravity
F=(6.7E-11)(9E-31)^2/(.001)^2
F=5.427E-65N
as you can see, electrical force is much much greater than gravitational force
make it a good day
F=9E9*(-1.6E-19)^2/(.001)^2
F=2.304E-22N
F=Gm1*m2/r^2 -- newtons law of gravity
F=(6.7E-11)(9E-31)^2/(.001)^2
F=5.427E-65N
as you can see, electrical force is much much greater than gravitational force
make it a good day