Ive read through the manual and have found nothing on it, so I'm assuming these calculators cant do what I'm looking for. Does anyone know if there's a way to find whether or not an infinite series converges? or a Series that does have an end converges? A general example of the type of equation I'm trying to put in is like in the picture below.
http://tinypic.com/r/2jbt7q0/5
--The answer is 1/192.. i already have that.
http://tinypic.com/r/2jbt7q0/5
--The answer is 1/192.. i already have that.
-
Not really, not without a third-party program at least.
To find the series (i.e. the sum of a sequence) when the bound are finite, you can use the [Stat] > Math > 5:sum( and [Stat] > Ops > 5:seq( commands together.
Example: to find the series of (1/4)^n from n = 1 to 5, you could type in:
sum(seq((1/4)^N,N,1,5))
Finding the series or convergence of an infinite series isn't really possible, short of trying to discern the function's end behavior from a graph or using a program (which may or may not be reliable), such as http://www.ticalc.org/archives/files/fil…
To find the series (i.e. the sum of a sequence) when the bound are finite, you can use the [Stat] > Math > 5:sum( and [Stat] > Ops > 5:seq( commands together.
Example: to find the series of (1/4)^n from n = 1 to 5, you could type in:
sum(seq((1/4)^N,N,1,5))
Finding the series or convergence of an infinite series isn't really possible, short of trying to discern the function's end behavior from a graph or using a program (which may or may not be reliable), such as http://www.ticalc.org/archives/files/fil…
-
This is a geometric series.
S = (1/4)^4 + (1/4)^5 + (1/4)^6 + ... + (1/4)^t
S * (1/4) = (1/4)^5 + (1/4)^6 + ... + (1/4)^t + (1/4)^(t + 1)
S - S * (1/4) = (1/4)^4 - (1/4)^(t + 1)
t goes to infinity
S * (1 - 1/4) = (1/4)^4 - (1/4)^(inf + 1)
S * (3/4) = (1/4)^4 - (1/4)^(inf)
S * (3/4) = 1/256 - 0
S = (4/3) * (1/256)
S = (1/3) * (1/64)
S = 1/192
A calculator is a tool, not a crutch. If you can't do something, why should your calculator do it?
S = (1/4)^4 + (1/4)^5 + (1/4)^6 + ... + (1/4)^t
S * (1/4) = (1/4)^5 + (1/4)^6 + ... + (1/4)^t + (1/4)^(t + 1)
S - S * (1/4) = (1/4)^4 - (1/4)^(t + 1)
t goes to infinity
S * (1 - 1/4) = (1/4)^4 - (1/4)^(inf + 1)
S * (3/4) = (1/4)^4 - (1/4)^(inf)
S * (3/4) = 1/256 - 0
S = (4/3) * (1/256)
S = (1/3) * (1/64)
S = 1/192
A calculator is a tool, not a crutch. If you can't do something, why should your calculator do it?