Factoring binomial? does anyone know how

3x^2-75

3x² - 75
= 3(x² - 25) . . . notice the difference of two squares
= 3(x - 5)(x + 5)

Dear Lselle,

3x^(2)-75

Factor out the GCF of 3 from the expression 3x^(2).
3(x^(2))-75

Factor out the GCF of 3 from the expression -75.
3(x^(2))+3(-25)

Factor out the GCF of 3 from 3x^(2)-75.
3(x^(2)-25)

The binomial can be factored using the difference of squares formula, because both terms are perfect squares. The difference of squares formula is a^(2)-b^(2)=(a-b)(a+b).
3(x-5)(x+5)

3x^2-75
= 3(x^2 - 25)
= 3(x + 5)(x - 5) answer//

Set equation to form equal to zero .
3x^2-75=0 : Divide by 3
x^2 - 25 = 0 : Addt 25 from both sides
X^2 = 25 : Take the square root of both sides
x+5

3x^2-75=
3(x^2-25)=
3(x+5)(x-5)

3(x-5)(x+5)