Please explain how to divide (x^3-7x-6) by (x+1) by long division

THE QUESTION IS
The polynomial p(x) is given by p(x)=x^3-7x-6
x+1 is a factor of p(x)
Express p(x)=x^3-7x-6 as the product of three linear factors
So one is (x+1) and I need to find the other two, and so Im trying to divide (x^3-7x-6) by (x+1) because I cant do it the short way

thank you

x^2-x-6
x+1 [x^3+0x^2-7x-6]
- x^3+1x^2
-x^2-7x
- -x^2-1x
-6x-6
-6x-6
0
Then factorise x^2-x-6

(x-3)(x+2)