That's sqrt of x, plus 1 over 6 sqrt of x, all to the power of 2.
and what is is usual method to go about finding the anti-derivative of this kind of function?
Thanks.
and what is is usual method to go about finding the anti-derivative of this kind of function?
Thanks.
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the expression becomes
x + 1/(36x) + 1/3
int = 1/2 x^2 + 1/36 * ln x + 1/3 x + C
x + 1/(36x) + 1/3
int = 1/2 x^2 + 1/36 * ln x + 1/3 x + C