Suppose that 0.010 mol of each of the following compounds is dissolved (separately) in 1 L of water: BaCl2, K4[Fe(CN)6], [Cr(NH3)4Cl2]Cl, [Fe(NH3)3Cl3]. Rank the resulting four solutions in order of their conductivity, from lowest to highest.
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at 0.01 M you can assume to first order most is dissolved and ionized
thus your problem boils down to how many ions
BaCl2, 3 ions lowest #1
K4[Fe(CN)6], 11 ions highest #4
[Cr(NH3)4Cl2]Cl, 8 ions #3
[Fe(NH3)3]Cl3 7 ions #2
thus your problem boils down to how many ions
BaCl2, 3 ions lowest #1
K4[Fe(CN)6], 11 ions highest #4
[Cr(NH3)4Cl2]Cl, 8 ions #3
[Fe(NH3)3]Cl3 7 ions #2