Please help me with these 2 math problems

solve each system of equation be substitution or elimination
1) 4x+6y=170
3x+8y=180

2)5x+2y=4
3y-4x=-40

4x+6y=170
3x+8y=180

3(4x+6y=170)
-4(3x+8y=180)

12x+18y=510
-12x-32y=-720
----------------------
-14y=-210
y=-210/14
y=15

if y=15 then x= 4x+90=170 4x=80 x=20

5x+2y=4
3y-4x=-40

5x+2y=4
-4x+3y=-40
-----------------------

-3(5x+2y=4)
2(-4x+3y=-40)

-15x-6y=-12
-8x+6y=-80
----------------------
-23x=-92
x=4 if x=4 then y=-8

They're both candidates for the elimination method:

1) 4x+6y=170
3x+8y=1

Multiply through the first equation by 3 and the second by 4 to match the x coefficients:

12x + 18y = 510
12x + 24y = 720

Subtract the first one from the second:

12x + 24y = 720
-(12x + 18y = 510)
------------------------
6y = 210

y = 35

Substitute 35 for y in either original equation to solve for x.


2)5x+2y=4
3y-4x=-40

Rewrite the second equation into the same form as the first one:

5x + 2y = 4
-4x + 3y = -40

Follow the process above multiplying equation 1 by 4 and equation 2 by 5 to match the x coefficients. Then add the equations to eliminate x and solve for y.

These are simultaneous leaner equation and there are many methods to solve them but are easy ....but are quit long to do the working here sorry ...! :(