As limit x approaches infinity

does the limit equal 0 or is there no limit?

The limit can be anything, depending on the function, which you neglected to provide.

Edit:
Seeing as you still haven't provided any function, I'll show you with examples.

ex1: f(x) = x

lim as x→∞ f(x) = ∞
In this case, the limit is infinity. Some high school teachers will teach that the limit does not exist, however.

ex2: f(x) = 1/x
lim as x→∞ f(x) = 1/∞ = 0
Limit is 0

ex3: f(x) = 2x²
limit is ∞ as x→∞

ex4: f(x) = (x² + x + 1) / (x² + 2x + 1)
limit is 1 as x→∞ because the degrees of the numerator and denominator are the same. You only consider the ratio of the highest powers. In other words, you can divide each term by x² to get
f(x) = (1 + 1/x + 1/x²) / (1 + 2/x + 1/x²)
limit by direct sub is (1 + 0 + 0)/(1+0+0) = 1

ex5: f(x) = x³ / (x²+1)
lim is infinity as x→∞ because the numerator is of a higher degree.

ex6: f(x) = x / (x²+1)
limit is 0 as x→∞ because the numerator's degree is lower.

ex7: f(x) = 3x / (4x + 1)
limit is 3/4 as x→∞ because the degrees of the num and denom are equal, so just look at the ratio of the coefficients.

As I said before, it depends on the function.

The limit applies to the value of a function of x, as x approaches infinity. You haven't said what the function is, so there is no way to know the limit.

If your function is f(x) = x, which you are implying... yes.