Can anybody solve this Quadratic problem by factoring ( without using Quadratic formula) (x-3)(x-4)=34/(33^2)

Start solving by completing square:
(x-3)(x-4)=34/(33^2)
x^2 - 7x + 12 = 34/1089
x^2 - 7x = 34/1089 -12
x^2 - 7x + 49/4 = 49/4 - 13034/1089
(x - 7/2)^2 = 1225/4356 => go to #2 below for solution by factoring:
x - 7/2 = ±35/66
x = 7/2(1 ± 5/33)
x = 7/2( 28/33) , x = 7/2(38/33)
x = 98/33 , x = 133/33

#2 solution by factoring:
(x - 7/2)^2 = 1225/4356
(x - 7/2)^2 - (35/66)^2 = 0 => factor using difference of squares:
(x - 7/2 + 35/66) (x - 7/2 - 35/66) = 0
(x - 98/33)(x - 133/33) = 0 => factored form, using zero products property:
x = 98/33 , x = 133/33

Regards.